Question 421069
{{{ 3x + 4y = 12}}}
The x-intercept is at {{{y = 0}}}
{{{ 3x + 0 = 12 }}}
{{{ 3x = 12 }}}
{{{ x = 4}}}
Must find the midpoint of  (4,0) and (6,4)
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{{{ x[m] = (4 + 6)/2 }}}
{{{ x[m] = 5 }}}
and
{{{ y[m] = (4 + 0)/2 }}}
{{{y[m] = 2 }}}
The midpoint is at (5,2)