Question 421036
{{{ 49x^2 - 25 = 0 }}}
{{{ 49x^2 = 25 }}}
{{{ (7x)^2 = 5^2}}}
Take the square root of both sides
{{{ 7x = 5 }}}
{{{x = 5/7}}}
and, taking the negative square root of  {{{5^2}}}
{{{7x = -5}}}
{{{x = -5/7}}}
The roots are 5/7 and -5/7
check answer:
{{{x = 5/7}}}
{{{ x - 5/7 = 0 }}}
and
{{{x = -5/7}}}
{{{ x + 5/7 = 0 }}}
{{{ (x - 5/7)*( x + 5/7) = 0 }}}
{{{ x^2 - 25/49 = 0 }}}
{{{x^2 = 25/49}}}
{{{ 49x^2 = 25 }}}
OK