Question 420900

a. there are no restrictions

no. of ways = 12C4  = 495


b. both jim and mary must be on the committee

no.of ways = 10C2 = 45



c. either jim or mary (not both) must be on the committee

no. of ways when jim on the committee but mary not = 10C3 = 120

no. of ways when mary on the committe but jim not = 10C3 = 120

total ways = 120+120 = 240