Question 420917
Given line:
{{{-2x + 3y = 3 }}}
{{{ 3y = 2x + 3 }}}
{{{ y = (2/3)*x + 1 }}}
This is in the form {{{y = mx + b }}} where
{{{m}}} = slope
The line parallel to this line must also have
slope = 2/3
The x-intercept is where {{{y = 0}}}
I can say now
{{{ y = (2/3)*x + b }}} goes through the point (4,0)
{{{ 0 = (2/3)*4 + b }}}
{{{ b = -(2/3)*4 }}}
{{{ b = -(8/3) }}}
The equation is:
{{{ y = (2/3)*x - 8/3 }}}
Here's a plot of both lines:
{{{ graph( 400, 400, -6, 10, -10, 6, (2/3)*x + 1, (2/3)*x - 8/3) }}}