Question 420633
Trains A and B are traveling in the same direction on parallel tracks.
 Train A is traveling at 80 miles per hour and Train B is traveling at 100 miles per hour.
 Train A passes a station at 9:20 am.
If Train B passes the same station at 9:32 am, at what time will Train B catch up to Train A?
:
From the given information, we know that train B is 12 min (1/5 hr) behind
 train A, when train A passes the station
:
The distance between the trains at this time: {{{1/5}}} * 100 = 20 mi
:
Let t = time required for train B to catch train A
:
write a distance equation: Dist = speed * time
:
Train B travel dist = Train A travel dist + 20 mi
100t = 80t + 20 
100t - 80t = 20
20t = 20
t = {{{20/20}}}
t = 1 hr for B to catch A
:
9:20 AM + 1.00 = 10:20 AM, B catches A