Question 420696
Find the perimeter and area of the rectangle with 
length of 8 sqrt (7) inches and 
width of 2 sqrt (7) - 3 sqrt(5) inches.
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Perimeter = 2(length + width)
P = 2(8sqrt(7) + 2sqrt(7)-3)
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P = 2(10sqrt(7) - 3)
P = [20sqrt(7) -6] inches
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Area = length * width
A = (8sqrt(7)*(2sqrt(7)-3))
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A = 16*7 - 24sqrt(7)
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Area = 112 - 24sqrt(7)
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Cheers,
Stan H.
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