<PRE><B>Question 44471</B>
Having problem with my assignment, would someone plesae help me?
Determine the point A(x,y) so that the points A(x,y),B(0,3),C(1,0),D(7,2) will be the vertices of a parallelogram.
DIAGONAL BISECT EACH OTHER IN A PARALLELOGRAM.HENCE
MID POINT OF AC={(X+1)/2,(Y+0)/2}=MID POINT OF BD ={(0+7)/2,(3+2)/2}
X+1=7....X=6
Y=5
A IS (6,5) 
Find an equation for the line with y-intercept 3 that is perpendicular to the line y=2/3(actaully the fraction two-thirds)x-4.
SLOPE OF GIVEN LINE =2/3
SLOPE OF ITS PERPENDICULAR =-3/2
HENCE EQN.IS 
Y=MX+C
Y=-3X/2+3
2Y+3X-6=0</PRE>