Question 420301
(x+8)(x-4)=-3(2x+5)

x^2-4x+8x-32=-6x-15
x^2+4x-32+6x+15=0
x^2+10x-17=0

Find the roots of the equation by quadratic formula

a= 1  , b =10   , c =-17     .

b^2-4ac=168

{{{x=(-b+-sqrt(b^2-4ac))/(2a)}}}


{{{x1=(-10+sqrt(168))/(2)}}}
x1=1.48
...
{{{x2=(-10-sqrt(168))/(2)}}}
x2=-11.48