Question 44493
Total measure of a triangle = 180 degrees
Triangle A = {{{x/5-2}}}
Triangle B = {{{x/2-5}}}
Triangle C = x
EQUATION:
{{{(x/5-2)+(x/2-5)+(x)=180}}}
Multiply the whole equation by 10 and simplfy
2x-20+5x-50+10x=1800
17x=1870
x=110
Trianlge A = {{{110/5-2}}} =20
Triangle B = {{{110/2-5}}}=50
Hence, the 3 angles are 50, 20 and 110 degree
Paul.