Question 419876
{{{lnx+ln(x+3)=1}}}
{{{ln x(x+3)=1}}}
{{{x(x+3)= e^1}}}
{{{x^2+3x= 2.718}}}
{{{x^2+3x-2.718= 0}}}
Solve by applying the quadratic formula to give:
x = {0.729, -3.729}
we can throw out the negative solution leaving:
x = 0.729
.
Details of quadratic formula follows:
.
*[invoke quadratic "x", 1, 3, -2.718281828 ]