Question 419870
 Find the perimeter and area of a right triangle if the shortest side is 9 in. and the longest side is 41 in. Include correct units with each part of your solution.
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Since it is a "right triangle" we can apply Pythagorean theorem to find the third side:
Let x = third side
then
x^2 + 9^2 = 41^2
x^2 + 81 = 1681
x^2 = 1600
x = 40 inches 
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perimeter = 40 + 9 + 41 = 90 inches