Question 419693
A certain number of nickels, two more dimes than nickels and two more quarters than dimes is worth $1.60.
 Find how many of each kind there are
:
Let n = no. of nickels
Let d = no. of dimes
Let q = no. of quarters
:
Write an equation for each phrase
:
 "two more dimes than nickels"
d = n + 2
or 
n = d - 2
:
"and two more quarters than dimes"
q = d + 2
:
"is worth $1.60."
.05n + .10d + .25q = 1.60
:
In the above equation; replace n with (d-2), replace q with (d+2), find d
.05(d-2) + .10d + .25(d+2) = 1.60
.05d - .10 + .10d + .25d + .5 = 1.60
Combine like terms
.05d + .10d + .25d - .10 + .50 = 1.60
.40d + .40 = 1.60
.40d = 1.60 - .40
.4d = 1.20
d = 1.20/.4
d = 3 dimes
:
I'll let you find the nickels and quarters from the other equations and set up your table