Question 419667
We can say that if the propeller driven plane flies x kilometers at 200 km/h, then the jet will fly 3x kilometers, because the jet is going three times as fast (use Distance = rate*time to verify this). Their total distance apart is 3000 km, so


3x + x = 3000 km


4x = 3000 km


x = 750 km


We wish to find 3x, because this is the length the jet traveled. Hence, 3x = 3(750 km) = 2250 km.

A graph doesn't suit this problem very well as it is merely a simple algebraic equation, but I'll graph the propeller plane's distance over time versus the jet's:


{{{graph(200, 200, 0, 5, 0, 3000, 200x, 600x)}}} (note that the y-axis increments far more than the x-axis. The jet's motion is shown in green)