Question 419579
The midpoint of the line segment is: (2-6)/2=-2 and (4-2)/2=1, (-2,1)
The slope of the line that pases at points (-2,1) and (8,7) is m=(1-7)/(-2-8)=3/5
The equation of the line with slope 3/5 and point (8,7) is: y-7=3/5(x-8) or
5(y-7)=3(x-8), 3x-5y=-11.