Question 419608
it must be:
{{{27c^2+108c+108=0}}}
{{{27(c^2+4c+4)=0}}}
{{{27(c^2+2*2c+2^2)=0}}}
{{{27(c+2)^2}}}=0
27 is non equal with zero
so the other factor must get zero:
{{{(c+2)^2=0}}}
{{{(c+2)=0}}}
c=-2