<PRE><B>Question 419468</B>
8 gal. of a 80% alcohol solution was mixed with 12 gal. of pure water. What is the concentration of the mixture?
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Equation:
alcohol + alcohol = alcohol
0.80*8 + 0*12 = x(8+12)
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Multiply thru by 100 to get:
80*8  = 100x(20)
640 = 2000x
x = 0.32
The concentration of the mixture is 32%
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Cheers,
Stan H.
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A) 30% B) 32% C) 10% D) 40%
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