Question 419413
{{{(2x+1)^1/3=8^1/3}}}


{{{1/(root(3,(2x+1)))=1/root(3,8)}}}.....since nominator are equal, then

 denominators must be equal too


{{{(root(3,(2x+1)))=root(3,8)}}}


Raise both sides to the power {{{3}}},

=>{{{ 2x +1= 8}}}

=> {{{2x  = 8-1}}}

=> {{{2x  = 7}}}

=> {{{x  = 7/2}}}

check:

{{{(2(7/2)+1)^(1/3)=8^(1/3)}}}


{{{1/(root(3,(2(7/2)+1)))=1/root(3,8)}}}...Raising both sides to the power 3

{{{1/2(7/2)+1=1/8}}}


{{{2(7/2)+1=8}}}

{{{7+1=8}}}

{{{8=8}}}