Question 419345


{{{5n^2-7n+2=0}}}.....factor...replace {{{-7n}}} with {{{-5n-2n}}}

{{{5n^2-5n-2n+2=0}}}...group first to and second two terms

{{{(5n^2-5n)-(2n-2)=0}}}

{{{5n(n-1)-2(n-1)=0}}}

{{{(5n-2)(n-1)=0}}}

if {{{5n-2=0}}}....->...{{{n=2/5}}}

if {{{n-1=0}}}....->...{{{n=1}}}


so, your solutions are:

{{{n=2/5}}} or {{{n=1}}}