Question 419328
First, let's rearrange the terms:

{{{2x^3 - 10 + 4x^2 - 5x}}} = {{{2x^3 + 4x^2 - 5x - 10}}}

Now, lets take {{{2x^2}}} out of the first two terms:
{{{2x^3 + 4x^2 - 5x - 10}}} = {{{2x^2}}}(x + 2) - 5x - 10

Now, lets take out -5 from the second two terms:
{{{2x^2}}}(x + 2) - 5x - 10 = {{{2x^2}}}(x + 2) - 5(x + 2)

Notice now that x + 2 is a factor in both terms, so we can factor that out, too:
(x + 2)({{{2x^2}}} - 5)

There's your factoring by grouping.