Question 419256
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Hi
finding all zeros of the function. 
f(x)=x^3-3x^2-6x+8  
      x^3-3x^2-6x+8   = 0  |If x = 1 then zero (1-3-6+8 = 0 )
   (x -1)(x-4)(x+2) =0  |Dividing x^3-3x^2-6x+8   by (x-1)
   ( x-1)=0  x = 1
    (x-4)=0  x = 4
    (x+2)=0  x = -2