Question 418795
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Hi
4x^2-4x+3=0
Move the constant term to the right side of the equation
4x^2-4x=-3  
Multiply each term in the equation by four times the coefficient of the x^2 term 
64x^2 -64x = -48 
Square the coefficient of the original x term and add it to both sides of the equation 
64x^2 -64x + 16 = -48 + 16
Take the square root of both sides and complete as shown
(8x -4)^2 =(-32)
(8x -4) = ± sqrt(-32)
      x = (4 ± sqrt(-32))8

{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
{{{x = (4 +- sqrt( -32))/(8) }}}