Question 419110
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Hi
f(x)=x+4 and g(x)=x^2 -4
 (f+g)(x) = x+4 + x^2 - 4 = x^2 + x
 (f+g)(x) = x^2 + x
 (f+g)(2) = 2^2 + 2 = 6

f(x)=x^2 -16 and g(x)=4-x
 (f+g)(x) =  x^2 - 16 + 4- x 
(f+g)(x) = x^2 -x -12
(f+g)(-3) = (-3)^2 -(-3) -12 = 0