Question 418953
Write the equation of the axis of symmetry, and find the coordinates of the vertex of the graph of each function. Idetify the vertex as a maximum or minimum. Then graph the function. The first ones are REALLY HARD. However, I'll give an easy one so I can see it all done so I can figure out the hard ones. The problem is : 
y = 3x^2 - 6x + 4 
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Since 3 is positive the parabola opens up.
It therefore has a minimum point.
That point occurs when x = -b/2a = 6/(2*3) = 1
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The corresponding y-value is f(1) = 3-6+4 = 1
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So the vertex is (1,1)
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The axis of symmetry is a vertical line thru the vertex.
Its equation is x = 1.
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Cheers,
Stan H.