Question 418744
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Hi
 Note: The probability of x successes in n trials is: 
P = nCx* {{{p^x*q^(n-x)}}} where p and q are the probabilities of success and failure 
respectively. In this case p = .20 and q = .80
nCx = {{{n!/(x!(n-x)!)}}}  n =100
probability that between 17% and 22% of 100 randomly selected pregnancies are classified as premature?
P( >22)  - P(<17) = .8077 - .1923 = .6154