Question 418692
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Hi
NORMSINV(0.9) = 1.28 (using Excel function)
Value may also easily be found in a Table for:
 "Percentiles of the Standard Normal Distribution"
 1.28 = X -84 /8
 8(1.28)+84 = X
 10.25 + 84 = 94.25 or 95 would be minumum passing grade

Note: Using X = 94  gives 10/8 = 1.25 which doesn't get You into the 90%