Question 418651
<font face="Times New Roman" size="+2">


One side of your triangle is 135'.  Another side is 55'.  The included angle is *[tex \Large 32^\circ\ +\ 90^\circ\ =\ 122^\circ].  Hence, if *[tex \Large x] is the length of the guy wire, then:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ =\ \sqrt{(135)^2\ +\ (55)^2\ -\ 2(135)(55)\cos(122^\circ)}]


Just do the arithmetic.


Hint:


If *[tex \Large 90^\circ\ <\ \varphi\ \leq\ 180^\circ] then *[tex \Large \cos(\varphi)\ <\ 0]


Since all of your given length measurements were to the nearest whole foot, the answer should also be expressed to the nearest whole foot.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
<div style="text-align:center"><a href="http://outcampaign.org/" target="_blank"><img src="http://cdn.cloudfiles.mosso.com/c116811/scarlet_A.png" border="0" alt="The Out Campaign: Scarlet Letter of Atheism" width="143" height="122" /></a></div>
</font>