Question 418527
  <pre><font face = "Tohoma" size = 4 color = "indigo"><b>
Hi
one integer is 5 less than 2 times another 
Let x and (2x-5) represent the integers
Question states***
   x(2x-5)=12
  2x^2-5x-12 = 0
factoring
 (2x+3)(x-4)=0 |Note:SUM of the inner product(3x) and the outer product(-8x) = -5x
 (2x+3) = 0   Tossing out fractional answer
 (x-4)=0  x = 4  the Integers are 4 and 3

CHECKING our Answer***
  3*4 = 12