Question 418574
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Hi
Note: The probability of x successes in n trials is: 
P = nCx* {{{p^x*q^(n-x)}}} where p and q are the probabilities of success and failure 
respectively. In this case p = .60 and q = .40
nCx = {{{n!/(x!(n-x)!)}}}  n = 20 and x = 10
P(>10 passing out of 20) = .7553 = P(11) + P(12)+...P(20)
for example:
P(11)= 167960(.6)^11).4)^9 = .1597    | 20C11 = 167960