Question 418401
I'll assume that the equation is 
{{{36^(x-5) = (1/6)^(11-x)}}}

<==> {{{6^(2*(x-5)) = 6^(x - 11)}}}
<==> 2(x-5) = x - 11
==> 2x - 10 = x - 11
==> x = 10-11
x = -1.