<PRE><B>Question 418423</B>
Assume the problem is:
{{{10^(x+3) = 6^(2x)}}}
using common logs we have 
{{{log(10^(x+3)) = log(6^(2x))}}}
log equiv of exponents
{{{(x+3)log(10) = 2x*log(6)}}} 
we know the log of 10 = 1, therefore
x + 3 = 2x*.778
x + 3 = 1.556x
3 = 1.556x - x
3 =.556x
x = {{{3/.556}}}
x = 5.393
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Check this on your calc: enter 10^8.393 and 6^10.786, should be close to the same value
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