Question 418405

total no. of ways to withdrawn ball 10 times = 10*10..10times = 10^10


total no. of ways to put two 1's but not near = 36

no. of ways to withdrawn ball 10 times when two 1's appear but not near 

= 36 * 9^8 

(on another 8 places, any one of 2-10 can appear i.e except 1)

probability = (36 * 9^8) / (10^10) 



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