Question 418138
over a yr period 20% of the cars will need to be repaired once, 
7% repairs twice, 3% will require three or more. 
if you own two cars what is the probability that neither will need to be repaired? 
I figured out the probability for one car but dont understand how to get 2 cars.
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You have to assume that repairs on cars are independent events;
my lemon does make your car a lemon.
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P(a car will need repair) = 0.30
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P(2 need repairs) = 0.3^2 = 0.09
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Cheers,
Stan H.
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