Question 418089
  <pre><font face = "Tohoma" size = 4 color = "indigo"><b>
Hi
Using the vertex form of a parabola, {{{y=a(x-h)^2 +k}}} where(h,k) is the vertex
y=2x^2-6x-14    |completing the square to put into the vertex form
y= 2(x-3/2)^2 -9/2 -14
y= 2(x-3/2)^2 -37/2  |vertex Pt(3/2,-37/2)  x = 3/2 the line of symmetry
CHECKING our Answer***
{{{drawing(300,300, -20,20,-20,20, blue(line(1.5,-20,1.5,20))  , grid(1),
circle(1.5, -18.5,0.3),
graph( 300, 300, -20,20,-20,20,2x^2-6x-14))}}}