Question 418069
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Hi
Sketch the graph of y= - sqrt(x+2)
Note: Pt(-2,0) and III and IV quadrant portions of the parabola: x = y^2 - 2 
{{{drawing(300,300, -6, 6, -6, 6, grid(1),
circle(-2, 0,0.2),
locate(4.3,4.6,"I"),
locate(-4.3,4.6,"II"),
locate(-4.3,-4.6,"III"),
locate(4.3,-4.6,"IV"),
graph( 300, 300,-6,6,-6,6,0,-(x+2)^.5)) }}}