Question 417795
{{{int((6x^2 + 4x), dx, 1, 3)
= (6(x^3/3) + 4(x^2/2))[1]^3

=(2x^3 + 2x^2)[1]^3

= 2*3^3 + 2*3^2 - 2*1^3 - 2*1^2

= 54 + 18 - 2 - 2

= 68



}}}