Question 44337
{{{(3m + 12)/(m^2 - 4) = (-2m^2 + 3m + 6)/(m^2 - 4) + (2m - 4)/(m - 2)}}}
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{{{((3m + 12)(m^2 - 4))/(m^2 - 4) = ((-2m^2 + 3m + 6)(m^2 - 4))/(m^2 - 4) + ((2m - 4)(m^2 - 4))/(m - 2)}}}
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{{{3m + 12 = -2m^2 + 3m + 6 + (2m - 4)(m + 2)}}}
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{{{3m + 12 = -2m^2 + 3m + 6 + 2m^2 - 8}}}
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{{{12 = 6 - 8}}}
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{{{12 = -2}}}
Twelve does not equal negative two, so there are no possible solutions.