Question 417836
the first team of workers received 50kg of cement less than second team.
 every hour of work first team was using 150kg of cement while second team used 200kg,
 in 3 hours the first team had 1.5 times as much remaining cement as second team.
 how much cement was delivered to each team.
:
Let a = amt of cement delivered to the 2nd team
then
(a-50) = amt delivered to the 1st team
:
1st team remains = 1.5 times 2nd team remains
(a-50) - 3(150) = 1.5[a - 3(200)]
a - 50 - 450 = 1.5(a - 600)
a - 500 = 1.5a - 900
-500 + 900 = 1.5a - a
400 = .5a
a = 800 kg delivered to the 2nd team
then
800 - 50 = 750 kg for the 1st team
:
:
Check this by find the actual amt each had remaining
Team 1: 750 - 3(150) = 300 kg
Team 2: 800 - 3(200) = 200 kg
300 is 1.5*200