Question 5699
with powers, there are very few rules to learn:


{{{a^mxa^n}}} is {{{a^(m+n)}}}

{{{a^m/a^n}}} is {{{a^(m-n)}}}

{{{(a^m)^n}}} is {{{a^(mn)}}}


these are the basic three...apply them to your question {{{a^(2m)b^(m+1)/a^(m)b}}}


so, the a terms: {{{a^(2m)/a^m}}}: we have division, so powers subtract: 2m-m is m --> {{{a^m}}}.


so, the b terms: {{{b^(m+1)/b}}}: we have division again, so m+1-1 is m --> {{{b^m}}}.


So, complete answer is {{{a^m*b^m}}}



jon.