Question 417819
Let {{{d}}} = number of dimes
Let {{{n}}} = number of nickels
given:
{{{n = 5d}}}
{{{5n + 10d = 105}}} (in cents)
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By substitution:
{{{5d + 10d = 105}}}
{{{15d = 105}}}
{{{d = 7}}}
and, since
{{{n = 5d}}}
{{{n = 35}}}
She has 35 nickels and 7 dimes