Question 417441
ind f(x) * g(x)
f(x)= 2x^3/2, g(x)= 3x^1/3
:
All this means is:
:
 {{{2x^(3/2)}}} * {{{3x^(1/3)}}}; (the numerators are 3 and 1
:
When you multiply, you add exponents:
:
{{{6x^((3/2)+(1/3))}}}
:
Common denominators is 6
:
{{{6x^((9/6)+(2/6))}}}; (the numerators are 9 and 2
Which is
{{{6x^(11/6)}}}; numerator is 11