Question 417624
A recent study of cardiovascular risk factors reports that 30% of adults meet the criteria for hypertension. If 15 adults are assessed, what is the probability that:
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Binomial Problem with n=15 and p = 0.3
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a. Exactly 15 meet the criteria for hypertension?:::0.3^15
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b. None meet the criteria for hypertension?::0.7^15
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c. Less than or equal to 7 meet the criteria for hypertension?
binomcdf(15,0.3,7) = 0.9500
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Diastolic blood pressures are assumed to follow a normal distribution with a mean of 85 and a standard deviation of 12.
a. What proportion of people have diastolic blood pressures less that 90?
z(90) = (90-85)/12 = 0.4167
P(x<90) = P(z<0.4167) = normalcdf(-100,0.4167) = 0.6616
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b. What proportions have diastolic blood pressures between 80 and 90?
Find the z-values and find the proportion between them.
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c. If someone has a diastolic blood pressure of 100, what percentile does this represent?
On a normal distribution the probability of any particular value is zero.
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Cheers,
Stan H.