Question 417471
f(x)=e^x/2+1/2e^x; f'(x)=e^x/2-e^x/2e^2x and f''(x)=e^x/2-1/2[e^x2e^2x-e^2x(e^x)]/e^4x=e^x/2-e^3x/2e^4x.