Question 417517
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Hi
{{{sqrt(2x-1)+2 = x }}}
{{{sqrt(2x-1)= x-2 }}}
     2x - 1 = (x-2)(x-2)   |Squaring both sides of the EQ
     2x - 1 = x^2 - 4x + 4
  x^2 - 6x + 5 = 0
factoring
 (x-5)(x-1)= 0
 (x-1)= 0  x = 1   Extraneous  3 &#8800; 1
 (x-5)= 0  x = 5    |  {{{sqrt(9)+ 2 = 5 }}}