<PRE><B>Question 417491</B>
 divide and simplify
2x^2-7x-15/x^2-4 divided by 10x+15/x^2-4 
i know you have to multiply by the reciprocal which cancels out the x^2-4.
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Having canceled the (x^2-4) you have:
(2x^2-7x-15)/(10x+15)
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= (2x^2-10x+3x-15)/(5(2x+3))
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= (2x(x-5)+3(x-5))/(5(2x+3))
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= ((x-5)(2x+3))/(5(2x+3))
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= (x-5)/5
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Cheers,
Stan H.
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