Question 417171
find equation equidistant from 2,3 and line y=1 for set of all points

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Given data shows this is a parabola of the form: x^2=4py.
(2,3) would be the focus and y=1 would be the directrix.
The axis of symmetry is x=2 and the parabola opens upwards.
Since the vertex is equidistant from the focus and directrix, its coordinates are (2,2). Therefore, equation =(x-2)^2=4(y-2)or y-2=1/4(x-2)^2 or the more usual form, y=1/4(x-2)^2+2
See a graphical representation of this parabola below:

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{{{ graph( 300, 300, -10, 10, -10, 10, .25(x-2)^2+2) }}}