Question 417317
2^5 * 2^2 = 128


extract the "whole" fifth root


fifth root (2^5 * 2^2) = 2 [fifth root(2^2)]


7 / fifthroot(128) = 7 / {2 [fifth root(2^2)]}


to remove radical from the denominator
multiply by ___  [fifth root(2^3)] /  [fifth root(2^3)]


{7 [fifth root(2^3)]} / {2 [fifth root(2^2)]  [fifth root(2^3)]}


{7 [fifth root(2^3)]} / {2 [fifth root(2^5]}


{7 [fifth root(2^3)]} / 4