Question 417096
So the equation is as follows, -4x=8-2y We are supposed to graph.
:
-4x = 8 - 2y
Put the equation in the slope/intercept form, (y = mx + b)
Add 2y to both sides
-4x + 2y = 8
Add 4x to both sides
2y = 4x + 8
Divide thru by 2, (y has to have a coefficient of +1)
y = 2x + 4, this is slope intercept form
:
To graph this choose at least two values for x, and find y
x = -3
y = 2(-3) + 4
y = -6 + 4
y = -2
:
x = 0
y = 2(0) + 4
y = 4
:
x = +2
y = 2(2) + 4
y = 4 + 4
y = 8
:
From this we can make a table of values that you can graph
 x | y
-------
-3 |-2
 0 | 4
+2 | 8
:
Your graph should resemble this
{{{ graph( 300, 200, -6, 5, -6, 8, 2x+4) }}}
:
:
Did we generate some understanding here?