Question 417102

{{{-3x+2y=4}}} and 

{{{2x+3y=-15}}}....write them in {{{slope-intercept}}} form


{{{2y=3x+4}}}

{{{y=(3/2)x+2}}}.......slope {{{m=3/2}}}, {{{y-intercept}}} is {{{2}}}


{{{3y=-2x-15}}}

{{{y=-(2/3)x-5}}}.......slope {{{m1=-(2/3)}}}, {{{y-intercept}}} is {{{-5}}}


slope {{{m1=-(2/3)}}} is negative inverse of {{{m=3/2}}}, and lines are perpendicular


graph:

{{{ graph( 500, 500, -10, 10, -10, 10, (3/2)x+2,-(2/3)x-5) }}}