Question 417052
3x^2+4x-8=0
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 
x=(-4+-sqrt[4^2-4*3*-8])/2*3
x=(-4+-sqrt[16+96])/6
x=(-4+-sqrt112)/6
x=(-4+-10.583)/6
x=(-4+10.583)/6
x=6.583/6
x=1.097 ans.
x=(-4-10.583)/6
x=-14.853/6
x=-2.43 ans.