Question 416881
 
possible case for getting 9 is (4,5), (5,4),(6,3) ,(3,6)


probability of getting 9, i.e P(A) = 2/36 


probability of not getting 9, i.e P'(A) =  1 - P(A) = 1 - 2/36 = 34/36 


= 17/18